3x^2-4x+6=9x+4

Solution for 3x^2-4x+6=9x+4 equation:

3x^2-4x+6=9x+4

We move all terms to the left:

3x^2-4x+6-(9x+4)=0

We get rid of parentheses

3x^2-4x-9x-4+6=0

We add all the numbers together, and all the variables

3x^2-13x+2=0

a = 3; b = -13; c = +2;
Δ = b2-4ac
Δ = -132-4·3·2
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{145}}{2*3}=\frac{13-\sqrt{145}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{145}}{2*3}=\frac{13+\sqrt{145}}{6}
$